Difference between revisions of "AGGREGATE world"

Revision as of 12:01, 16 July 2015

#ENCODING
import io
import sys
sys.stdout = io.TextIOWrapper(sys.stdout.buffer, encoding='utf-16')
#MONGO
from pymongo import MongoClient
client = MongoClient()
client.progzoo.authenticate('scott','tiger')
db = client['progzoo']
#PRETTY
import pprint
pp = pprint.PrettyPrinter(indent=4)

Country Profile

For these questions you should use find() on the collection world

Show the name and population for the countries that have a population of at least 200 million.

pp.pprint(list(
    db.world.find({},{"name":1,"_id":0})
))

pp.pprint(list(

   db.world.find({"population":{"$gt":20000000}},{"name":1,"population":1"_id":0})

))

@@ Line 18: / Line 18: @@
 <div class=q data-lang="py3">
-Show the name for the countries that have a population of at least 200 million.
+Show the name and population for the countries that have a population of at least 200 million.
 <pre class=def>
 pp.pprint(list(
@@ Line 26: / Line 26: @@
 <div class=ans>
 pp.pprint(list(
-     db.world.find({"population":{"$gt":20000000}},{"name":1,"_id":0})
+     db.world.find({"population":{"$gt":20000000}},{"name":1,"population":1"_id":0})
 ))
 </div>
 </div>